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JEE Main PAPER - 1

JEE Main · 2018

180 questions · One at a time

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141
MCQ4 marks

If ∑i=19(xi−5)=9\sum_{i=1}^{9}(x_i - 5) = 9   and ∑i=19(xi−5)2=45\sum_{i=1}^{9}(x_i - 5)^2 = 45  , then the standard deviation of the 9 items x1,x2,…,x9x_1, x_2, \dots, x_9   is:

  • A.2Correct
  • B.3
  • C.9
  • D.4
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