JEE Main PAPER - 1

Let $f(x) = x^{2} + \frac{1}{x^{2}}$   and $g(x) = x - \frac{1}{x}$  , $x \in \mathbb{R} - \{-1, 0, 1\}$  . If $h(x) = \frac{f(x)}{g(x)}$  , then the local minimum value of $h(x)$   is: