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JEE Advance 2025 Paper 1

JEE Advance · 2025

94 questions · One at a time

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MCQ3 marks

The center of a disk of radius rr   and mass mm   is attached to a spring of constant kk  , inside a ring of radius R>rR > r  . The disk rolls without slipping. In equilibrium, the disk is at the bottom. Assuming small displacement, find the angular frequency ω\omega   where T=2π/ωT = 2\pi/\omega  .

  • A.23(gR−r+km)\sqrt{\frac{2}{3}(\frac{g}{R-r}+\frac{k}{m})}Correct
  • B.2g3(R−r)+km\sqrt{\frac{2g}{3(R-r)}+\frac{k}{m}}
  • C.16(gR−r+km)\sqrt{\frac{1}{6}(\frac{g}{R-r}+\frac{k}{m})}
  • D.14(gR−r+km)\sqrt{\frac{1}{4}(\frac{g}{R-r}+\frac{k}{m})}
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