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JEE Advance 2025 Paper 1

JEE Advance · 2025

94 questions · One at a time

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60
MCQ4 marks

Match the frequency distribution statistics. Sum of frequencies = 19, median = 6. (P) 7f1+9f27f_{1} + 9f_{2}   (Q) 19α19\alpha   (Mean dev. from mean) (R) 19β19\beta   (Mean dev. from median) (S) 19σ219\sigma^{2}   (Variance).

  • A.→ (5), (Q) → (3), (R) → (2), (S) → (4)
  • B.→ (5), (Q) → (2), (R) → (3), (S) → (1)
  • C.→ (5), (Q) → (3), (R) → (2), (S) → (1)Correct
  • D.→ (3), (Q) → (2), (R) → (5), (S) → (4)
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