← Back to practice

JEE Advance 2025 Paper 1

JEE Advance · 2025

94 questions · One at a time

Answers and solutions are AI-generated — please cross-check with your study materials.

View question paper
2
MCQ3 marks

Three students S1,S2S_1, S_2  , and S3S_3   are given a problem to solve. Consider the following events: UU  : At least one of S1,S2S_1, S_2  , and S3S_3   can solve the problem; VV  : S1S_1   can solve the problem, given that neither S2S_2   nor S3S_3   can solve the problem; WW  : S2S_2   can solve the problem and S3S_3   cannot solve the problem; TT  : S3S_3   can solve the problem. For any event EE  , let P(E)P(E)   denote the probability of EE  . If P(U)=12,P(V)=110P(U) = \frac{1}{2}, P(V) = \frac{1}{10}  , and P(W)=112P(W) = \frac{1}{12}  , then P(T)P(T)   is equal to

  • A.13/36Correct
  • B.1/3
  • C.19/60
  • D.1/4
2 of 94