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Gujarat Secondary and Higher Secondary Education Board · Gujarati · Class 10 · Basic Maths

Board exam · Basic Maths · 2026

15 questions · One at a time

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9
SHORT ANSWER2 marks

જો HCF(306,657)=9HCF(306, 657) = 9  આપેલ હોય, તો LCM(306,657)LCM(306, 657)  શોધો.

Answer

આપણે જાણીએ છીએ કે HCF(a,b)×LCM(a,b)=a×bHCF(a, b) \times LCM(a, b) = a \times b. અહીં a=306a = 306 અને b=657b = 657 છે. તેથી, 9×LCM=306×6579 \times LCM = 306 \times 657. LCM=306×6579=34×657=22338LCM = \frac{306 \times 657}{9} = 34 \times 657 = 22338. આમ, લસાઅ 2233822338 છે.
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