JEE Main PAPER - 1

The combustion of benzene (l) gives $CO_2(g)$   and $H_2O(l)$  . Given that heat of combustion of benzene at constant volume is $-3263.9\text{ kJ mol}^{-1}$   at $25^{\circ}C$  ; heat of combustion (in $\text{kJ mol}^{-1}$  ) of benzene at constant pressure will be: ($R = 8.314\text{ J K}^{-1}\text{ mol}^{-1}$  )