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JEE Main PAPER - 1

JEE Main · 2018

180 questions · One at a time

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126
MCQ4 marks

If the system of linear equations x+ky+3z=0x + ky + 3z = 0  , 3x+ky−2z=03x + ky - 2z = 0  , 2x+4y−3z=02x + 4y - 3z = 0   has a non-zero solution (x,y,z)(x,y,z)  , then xzy2\frac{xz}{y^2}   is equal to:

  • A.-30
  • B.30
  • C.-10
  • D.10Correct
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