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JEE Main PAPER - 1

JEE Main · 2018

180 questions · One at a time

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95
MCQ4 marks

A particle is moving in a circular path of radius aa   under the action of an attractive potential U=−k2r2U = -\frac{k}{2r^2}  . Its total energy is:

  • A.ZeroCorrect
  • B.−32ka2-\frac{3}{2}\frac{k}{a^2}
  • C.−k4a2-\frac{k}{4a^2}
  • D.k2a2\frac{k}{2a^2}
95 of 180
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