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JEE Advance 2025 Paper 1

JEE Advance · 2025

94 questions · One at a time

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SHORT ANSWER4 marks

Let f(x)>0f(x) > 0   and f(x+y)=f(x)f(y)f(x+y) = f(x)f(y)  . Let a1,...,a50a_{1}, ..., a_{50}   be in AP. If f(a31)=64f(a25)f(a_{31}) = 64f(a_{25})   and i=150f(ai)=3(225+1)\sum_{i=1}^{50} f(a_{i}) = 3(2^{25} + 1)  , find i=630f(ai)\sum_{i=6}^{30} f(a_{i})  .

Answer

96
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