57SHORT ANSWER4 marksLet α,β\alpha, \betaα,β be real numbers such that limx→01x3(α2∫0x11−t2dt+βxcosx)=2\lim_{x \to 0} \frac{1}{x^{3}} \left( \frac{\alpha}{2} \int_{0}^{x} \frac{1}{1-t^{2}} dt + \beta x \cos x \right) = 2limx→0x31(2α∫0x1−t21dt+βxcosx)=2 . Find α+β\alpha + \betaα+β .Answer2.4Log in to generate solution